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4+1/3x=-48-8x
We move all terms to the left:
4+1/3x-(-48-8x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
1/3x-(-8x-48)+4=0
We get rid of parentheses
1/3x+8x+48+4=0
We multiply all the terms by the denominator
8x*3x+48*3x+4*3x+1=0
Wy multiply elements
24x^2+144x+12x+1=0
We add all the numbers together, and all the variables
24x^2+156x+1=0
a = 24; b = 156; c = +1;
Δ = b2-4ac
Δ = 1562-4·24·1
Δ = 24240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24240}=\sqrt{16*1515}=\sqrt{16}*\sqrt{1515}=4\sqrt{1515}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(156)-4\sqrt{1515}}{2*24}=\frac{-156-4\sqrt{1515}}{48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(156)+4\sqrt{1515}}{2*24}=\frac{-156+4\sqrt{1515}}{48} $
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