4+10(2r-8)=64

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Solution for 4+10(2r-8)=64 equation:



4+10(2r-8)=64
We move all terms to the left:
4+10(2r-8)-(64)=0
We add all the numbers together, and all the variables
10(2r-8)-60=0
We multiply parentheses
20r-80-60=0
We add all the numbers together, and all the variables
20r-140=0
We move all terms containing r to the left, all other terms to the right
20r=140
r=140/20
r=7

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