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4+11x=2+5x+(2+6x)
We move all terms to the left:
4+11x-(2+5x+(2+6x))=0
We add all the numbers together, and all the variables
11x-(2+5x+(6x+2))+4=0
We calculate terms in parentheses: -(2+5x+(6x+2)), so:We get rid of parentheses
2+5x+(6x+2)
determiningTheFunctionDomain 5x+(6x+2)+2
We get rid of parentheses
5x+6x+2+2
We add all the numbers together, and all the variables
11x+4
Back to the equation:
-(11x+4)
11x-11x-4+4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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