4+12x-6(3x-2)+13=11+4(3-2x)

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Solution for 4+12x-6(3x-2)+13=11+4(3-2x) equation: 



4+12x-6(3x-2)+13=11+4(3-2x)

We move all terms to the left:

4+12x-6(3x-2)+13-(11+4(3-2x))=0

We add all the numbers together, and all the variables

12x-6(3x-2)-(11+4(-2x+3))+4+13=0

We add all the numbers together, and all the variables

12x-6(3x-2)-(11+4(-2x+3))+17=0

We multiply parentheses

12x-18x-(11+4(-2x+3))+12+17=0



We calculate terms in parentheses: -(11+4(-2x+3)), so:

11+4(-2x+3)

determiningTheFunctionDomain
4(-2x+3)+11

We multiply parentheses

-8x+12+11

We add all the numbers together, and all the variables

-8x+23

Back to the equation:

-(-8x+23)



We add all the numbers together, and all the variables

-6x-(-8x+23)+29=0

We get rid of parentheses

-6x+8x-23+29=0

We add all the numbers together, and all the variables

2x+6=0

We move all terms containing x to the left, all other terms to the right

2x=-6

x=-6/2

x=-3

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