4+2(2c+2)=16

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Solution for 4+2(2c+2)=16 equation: 



4+2(2c+2)=16

We move all terms to the left:

4+2(2c+2)-(16)=0

We add all the numbers together, and all the variables

2(2c+2)-12=0

We multiply parentheses

4c+4-12=0

We add all the numbers together, and all the variables

4c-8=0

We move all terms containing c to the left, all other terms to the right

4c=8

c=8/4

c=2

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