4+2(2y+4)=20

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Solution for 4+2(2y+4)=20 equation: 



4+2(2y+4)=20

We move all terms to the left:

4+2(2y+4)-(20)=0

We add all the numbers together, and all the variables

2(2y+4)-16=0

We multiply parentheses

4y+8-16=0

We add all the numbers together, and all the variables

4y-8=0

We move all terms containing y to the left, all other terms to the right

4y=8

y=8/4

y=2

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