4+2(2y+4)=20

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Solution for 4+2(2y+4)=20 equation:



4+2(2y+4)=20
We move all terms to the left:
4+2(2y+4)-(20)=0
We add all the numbers together, and all the variables
2(2y+4)-16=0
We multiply parentheses
4y+8-16=0
We add all the numbers together, and all the variables
4y-8=0
We move all terms containing y to the left, all other terms to the right
4y=8
y=8/4
y=2

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