4+2(3+2y)=6y-20

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Solution for 4+2(3+2y)=6y-20 equation: 



4+2(3+2y)=6y-20

We move all terms to the left:

4+2(3+2y)-(6y-20)=0

We add all the numbers together, and all the variables

2(2y+3)-(6y-20)+4=0

We multiply parentheses

4y-(6y-20)+6+4=0

We get rid of parentheses

4y-6y+20+6+4=0

We add all the numbers together, and all the variables

-2y+30=0

We move all terms containing y to the left, all other terms to the right

-2y=-30

y=-30/-2

y=+15

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