4+2(3x+3)=4x+20

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Solution for 4+2(3x+3)=4x+20 equation: 



4+2(3x+3)=4x+20

We move all terms to the left:

4+2(3x+3)-(4x+20)=0

We multiply parentheses

6x-(4x+20)+6+4=0

We get rid of parentheses

6x-4x-20+6+4=0

We add all the numbers together, and all the variables

2x-10=0

We move all terms containing x to the left, all other terms to the right

2x=10

x=10/2

x=5

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