4+2(6u-7)=-2(2u-2)+8u

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Solution for 4+2(6u-7)=-2(2u-2)+8u equation: 



4+2(6u-7)=-2(2u-2)+8u

We move all terms to the left:

4+2(6u-7)-(-2(2u-2)+8u)=0

We multiply parentheses

12u-(-2(2u-2)+8u)-14+4=0



We calculate terms in parentheses: -(-2(2u-2)+8u), so:

-2(2u-2)+8u

We add all the numbers together, and all the variables

8u-2(2u-2)

We multiply parentheses

8u-4u+4

We add all the numbers together, and all the variables

4u+4

Back to the equation:

-(4u+4)



We add all the numbers together, and all the variables

12u-(4u+4)-10=0

We get rid of parentheses

12u-4u-4-10=0

We add all the numbers together, and all the variables

8u-14=0

We move all terms containing u to the left, all other terms to the right

8u=14

u=14/8

u=1+3/4

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