4+2(6v+1)=102

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Solution for 4+2(6v+1)=102 equation: 



4+2(6v+1)=102

We move all terms to the left:

4+2(6v+1)-(102)=0

We add all the numbers together, and all the variables

2(6v+1)-98=0

We multiply parentheses

12v+2-98=0

We add all the numbers together, and all the variables

12v-96=0

We move all terms containing v to the left, all other terms to the right

12v=96

v=96/12

v=8

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