4+2(x-3)+1=4-3(x+1)

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Solution for 4+2(x-3)+1=4-3(x+1) equation:



4+2(x-3)+1=4-3(x+1)
We move all terms to the left:
4+2(x-3)+1-(4-3(x+1))=0
We add all the numbers together, and all the variables
2(x-3)-(4-3(x+1))+5=0
We multiply parentheses
2x-(4-3(x+1))-6+5=0
We calculate terms in parentheses: -(4-3(x+1)), so:
4-3(x+1)
determiningTheFunctionDomain -3(x+1)+4
We multiply parentheses
-3x-3+4
We add all the numbers together, and all the variables
-3x+1
Back to the equation:
-(-3x+1)
We add all the numbers together, and all the variables
2x-(-3x+1)-1=0
We get rid of parentheses
2x+3x-1-1=0
We add all the numbers together, and all the variables
5x-2=0
We move all terms containing x to the left, all other terms to the right
5x=2
x=2/5
x=2/5

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