4+2(x-3)+1=4-3(x+2)

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Solution for 4+2(x-3)+1=4-3(x+2) equation: 



4+2(x-3)+1=4-3(x+2)

We move all terms to the left:

4+2(x-3)+1-(4-3(x+2))=0

We add all the numbers together, and all the variables

2(x-3)-(4-3(x+2))+5=0

We multiply parentheses

2x-(4-3(x+2))-6+5=0



We calculate terms in parentheses: -(4-3(x+2)), so:

4-3(x+2)

determiningTheFunctionDomain
-3(x+2)+4

We multiply parentheses

-3x-6+4

We add all the numbers together, and all the variables

-3x-2

Back to the equation:

-(-3x-2)



We add all the numbers together, and all the variables

2x-(-3x-2)-1=0

We get rid of parentheses

2x+3x+2-1=0

We add all the numbers together, and all the variables

5x+1=0

We move all terms containing x to the left, all other terms to the right

5x=-1

x=-1/5

x=-1/5

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