4+2(x-5)=7-8(x-8)

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Solution for 4+2(x-5)=7-8(x-8) equation: 



4+2(x-5)=7-8(x-8)

We move all terms to the left:

4+2(x-5)-(7-8(x-8))=0

We multiply parentheses

2x-(7-8(x-8))-10+4=0



We calculate terms in parentheses: -(7-8(x-8)), so:

7-8(x-8)

determiningTheFunctionDomain
-8(x-8)+7

We multiply parentheses

-8x+64+7

We add all the numbers together, and all the variables

-8x+71

Back to the equation:

-(-8x+71)



We add all the numbers together, and all the variables

2x-(-8x+71)-6=0

We get rid of parentheses

2x+8x-71-6=0

We add all the numbers together, and all the variables

10x-77=0

We move all terms containing x to the left, all other terms to the right

10x=77

x=77/10

x=7+7/10

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