4+2(z-2)=-3z+4=

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Solution for 4+2(z-2)=-3z+4= equation: 



4+2(z-2)=-3z+4=

We move all terms to the left:

4+2(z-2)-(-3z+4)=0

We multiply parentheses

2z-(-3z+4)-4+4=0

We get rid of parentheses

2z+3z-4-4+4=0

We add all the numbers together, and all the variables

5z-4=0

We move all terms containing z to the left, all other terms to the right

5z=4

z=4/5

z=4/5

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