4+2(z-2)=6z+1

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Solution for 4+2(z-2)=6z+1 equation: 



4+2(z-2)=6z+1

We move all terms to the left:

4+2(z-2)-(6z+1)=0

We multiply parentheses

2z-(6z+1)-4+4=0

We get rid of parentheses

2z-6z-1-4+4=0

We add all the numbers together, and all the variables

-4z-1=0

We move all terms containing z to the left, all other terms to the right

-4z=1

z=1/-4

z=-1/4

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