4+2=(1+3z)

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Solution for 4+2=(1+3z) equation: 



4+2=(1+3z)

We move all terms to the left:

4+2-((1+3z))=0

We add all the numbers together, and all the variables

-((3z+1))+4+2=0

We add all the numbers together, and all the variables

-((3z+1))+6=0



We calculate terms in parentheses: -((3z+1)), so:

(3z+1)

We get rid of parentheses

3z+1

Back to the equation:

-(3z+1)



We get rid of parentheses

-3z-1+6=0

We add all the numbers together, and all the variables

-3z+5=0

We move all terms containing z to the left, all other terms to the right

-3z=-5

z=-5/-3

z=1+2/3

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