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4+2b=5+5(b+4)
We move all terms to the left:
4+2b-(5+5(b+4))=0
We calculate terms in parentheses: -(5+5(b+4)), so:We get rid of parentheses
5+5(b+4)
determiningTheFunctionDomain 5(b+4)+5
We multiply parentheses
5b+20+5
We add all the numbers together, and all the variables
5b+25
Back to the equation:
-(5b+25)
2b-5b-25+4=0
We add all the numbers together, and all the variables
-3b-21=0
We move all terms containing b to the left, all other terms to the right
-3b=21
b=21/-3
b=-7
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