4+2n=3(n-2)+1

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Solution for 4+2n=3(n-2)+1 equation: 



4+2n=3(n-2)+1

We move all terms to the left:

4+2n-(3(n-2)+1)=0



We calculate terms in parentheses: -(3(n-2)+1), so:

3(n-2)+1

We multiply parentheses

3n-6+1

We add all the numbers together, and all the variables

3n-5

Back to the equation:

-(3n-5)



We get rid of parentheses

2n-3n+5+4=0

We add all the numbers together, and all the variables

-1n+9=0

We move all terms containing n to the left, all other terms to the right

-n=-9

n=-9/-1

n=+9

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