4+2p=10((3/5)p-2)

Solution for 4+2p=10((3/5)p-2) equation:

4+2p=10((3/5)p-2)

We move all terms to the left:

4+2p-(10((3/5)p-2))=0


Domain of the equation: 5)p-2))!=0

p!=0/1

p!=0

p∈R


We add all the numbers together, and all the variables

2p-(10((+3/5)p-2))+4=0

We multiply all the terms by the denominator


2p*5)p-2))-(10((+4*5)p-2))+3=0

We add all the numbers together, and all the variables

2p*5)p-2))-(10(20p-2))+3=0

Wy multiply elements

10p^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$p=\frac{-b}{2a}=\frac{0}{20}=0$