4+2p=10(2/3p-2)

Solution for 4+2p=10(2/3p-2) equation:

4+2p=10(2/3p-2)

We move all terms to the left:

4+2p-(10(2/3p-2))=0


Domain of the equation: 3p-2))!=0

p∈R


We multiply all the terms by the denominator


2p*3p+4*3p-2))-(10(2-2))=0

We add all the numbers together, and all the variables

2p*3p+4*3p-2))-(100)=0

We add all the numbers together, and all the variables

2p*3p+4*3p=0

Wy multiply elements

6p^2+12p=0

a = 6; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·6·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*6}=\frac{-24}{12}
=-2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*6}=\frac{0}{12}
=0
$