4+2p=10(3/4p-2)

Solution for 4+2p=10(3/4p-2) equation:

4+2p=10(3/4p-2)

We move all terms to the left:

4+2p-(10(3/4p-2))=0


Domain of the equation: 4p-2))!=0

p∈R


We multiply all the terms by the denominator


2p*4p+4*4p-2))-(10(3-2))=0

We add all the numbers together, and all the variables

2p*4p+4*4p-2))-(101)=0

We add all the numbers together, and all the variables

2p*4p+4*4p=0

Wy multiply elements

8p^2+16p=0

a = 8; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·8·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*8}=\frac{-32}{16}
=-2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*8}=\frac{0}{16}
=0
$