4+2p=10*(3/5p-2)

Solution for 4+2p=10*(3/5p-2) equation:

4+2p=10(3/5p-2)

We move all terms to the left:

4+2p-(10(3/5p-2))=0


Domain of the equation: 5p-2))!=0

p∈R


We multiply all the terms by the denominator


2p*5p+4*5p-2))-(10(3-2))=0

We add all the numbers together, and all the variables

2p*5p+4*5p-2))-(101)=0

We add all the numbers together, and all the variables

2p*5p+4*5p=0

Wy multiply elements

10p^2+20p=0

a = 10; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·10·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*10}=\frac{-40}{20}
=-2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*10}=\frac{0}{20}
=0
$