4+2r+(3r+2)+2(r+1)=43

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Solution for 4+2r+(3r+2)+2(r+1)=43 equation: 



4+2r+(3r+2)+2(r+1)=43

We move all terms to the left:

4+2r+(3r+2)+2(r+1)-(43)=0

We add all the numbers together, and all the variables

2r+(3r+2)+2(r+1)-39=0

We multiply parentheses

2r+(3r+2)+2r+2-39=0

We get rid of parentheses

2r+3r+2r+2+2-39=0

We add all the numbers together, and all the variables

7r-35=0

We move all terms containing r to the left, all other terms to the right

7r=35

r=35/7

r=5

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