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4+2x=3x(x-7)
We move all terms to the left:
4+2x-(3x(x-7))=0
We calculate terms in parentheses: -(3x(x-7)), so:We get rid of parentheses
3x(x-7)
We multiply parentheses
3x^2-21x
Back to the equation:
-(3x^2-21x)
-3x^2+2x+21x+4=0
We add all the numbers together, and all the variables
-3x^2+23x+4=0
a = -3; b = 23; c = +4;
Δ = b2-4ac
Δ = 232-4·(-3)·4
Δ = 577
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{577}}{2*-3}=\frac{-23-\sqrt{577}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{577}}{2*-3}=\frac{-23+\sqrt{577}}{-6} $
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