4+3(2r+1)=19

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Solution for 4+3(2r+1)=19 equation:



4+3(2r+1)=19
We move all terms to the left:
4+3(2r+1)-(19)=0
We add all the numbers together, and all the variables
3(2r+1)-15=0
We multiply parentheses
6r+3-15=0
We add all the numbers together, and all the variables
6r-12=0
We move all terms containing r to the left, all other terms to the right
6r=12
r=12/6
r=2

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