4+3(3x-5)=6-3(2x+1)

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Solution for 4+3(3x-5)=6-3(2x+1) equation: 



4+3(3x-5)=6-3(2x+1)

We move all terms to the left:

4+3(3x-5)-(6-3(2x+1))=0

We multiply parentheses

9x-(6-3(2x+1))-15+4=0



We calculate terms in parentheses: -(6-3(2x+1)), so:

6-3(2x+1)

determiningTheFunctionDomain
-3(2x+1)+6

We multiply parentheses

-6x-3+6

We add all the numbers together, and all the variables

-6x+3

Back to the equation:

-(-6x+3)



We add all the numbers together, and all the variables

9x-(-6x+3)-11=0

We get rid of parentheses

9x+6x-3-11=0

We add all the numbers together, and all the variables

15x-14=0

We move all terms containing x to the left, all other terms to the right

15x=14

x=14/15

x=14/15

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