4+3(3y-5)=(2y-11+y)

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Solution for 4+3(3y-5)=(2y-11+y) equation:


Simplifying
4 + 3(3y + -5) = (2y + -11 + y)

Reorder the terms:
4 + 3(-5 + 3y) = (2y + -11 + y)
4 + (-5 * 3 + 3y * 3) = (2y + -11 + y)
4 + (-15 + 9y) = (2y + -11 + y)

Combine like terms: 4 + -15 = -11
-11 + 9y = (2y + -11 + y)

Reorder the terms:
-11 + 9y = (-11 + 2y + y)

Combine like terms: 2y + y = 3y
-11 + 9y = (-11 + 3y)

Remove parenthesis around (-11 + 3y)
-11 + 9y = -11 + 3y

Add '11' to each side of the equation.
-11 + 11 + 9y = -11 + 11 + 3y

Combine like terms: -11 + 11 = 0
0 + 9y = -11 + 11 + 3y
9y = -11 + 11 + 3y

Combine like terms: -11 + 11 = 0
9y = 0 + 3y
9y = 3y

Solving
9y = 3y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3y' to each side of the equation.
9y + -3y = 3y + -3y

Combine like terms: 9y + -3y = 6y
6y = 3y + -3y

Combine like terms: 3y + -3y = 0
6y = 0

Divide each side by '6'.
y = 0

Simplifying
y = 0

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