4+3(4v-2)=-2(2v-8)=4v

Solution for 4+3(4v-2)=-2(2v-8)=4v equation:

4+3(4v-2)=-2(2v-8)=4v

We move all terms to the left:

4+3(4v-2)-(-2(2v-8))=0

We multiply parentheses

12v-(-2(2v-8))-6+4=0


We calculate terms in parentheses: -(-2(2v-8)), so:

-2(2v-8)

We multiply parentheses

-4v+16

Back to the equation:

-(-4v+16)


We add all the numbers together, and all the variables

12v-(-4v+16)-2=0

We get rid of parentheses

12v+4v-16-2=0

We add all the numbers together, and all the variables

16v-18=0

We move all terms containing v to the left, all other terms to the right

16v=18

v=18/16

v=1+1/8