4+3(4v-3)=-3(4v-1)+8v

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Solution for 4+3(4v-3)=-3(4v-1)+8v equation: 



4+3(4v-3)=-3(4v-1)+8v

We move all terms to the left:

4+3(4v-3)-(-3(4v-1)+8v)=0

We multiply parentheses

12v-(-3(4v-1)+8v)-9+4=0



We calculate terms in parentheses: -(-3(4v-1)+8v), so:

-3(4v-1)+8v

We add all the numbers together, and all the variables

8v-3(4v-1)

We multiply parentheses

8v-12v+3

We add all the numbers together, and all the variables

-4v+3

Back to the equation:

-(-4v+3)



We add all the numbers together, and all the variables

12v-(-4v+3)-5=0

We get rid of parentheses

12v+4v-3-5=0

We add all the numbers together, and all the variables

16v-8=0

We move all terms containing v to the left, all other terms to the right

16v=8

v=8/16

v=1/2

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