4+3(4x-5)=9-5(2x+1)

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Solution for 4+3(4x-5)=9-5(2x+1) equation: 



4+3(4x-5)=9-5(2x+1)

We move all terms to the left:

4+3(4x-5)-(9-5(2x+1))=0

We multiply parentheses

12x-(9-5(2x+1))-15+4=0



We calculate terms in parentheses: -(9-5(2x+1)), so:

9-5(2x+1)

determiningTheFunctionDomain
-5(2x+1)+9

We multiply parentheses

-10x-5+9

We add all the numbers together, and all the variables

-10x+4

Back to the equation:

-(-10x+4)



We add all the numbers together, and all the variables

12x-(-10x+4)-11=0

We get rid of parentheses

12x+10x-4-11=0

We add all the numbers together, and all the variables

22x-15=0

We move all terms containing x to the left, all other terms to the right

22x=15

x=15/22

x=15/22

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