4+3(4y+2)=12y+10

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Solution for 4+3(4y+2)=12y+10 equation:



4+3(4y+2)=12y+10
We move all terms to the left:
4+3(4y+2)-(12y+10)=0
We multiply parentheses
12y-(12y+10)+6+4=0
We get rid of parentheses
12y-12y-10+6+4=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0

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