4+3(9-(1+x))=-3(x-1)-4+x

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Solution for 4+3(9-(1+x))=-3(x-1)-4+x equation: 



4+3(9-(1+x))=-3(x-1)-4+x

We move all terms to the left:

4+3(9-(1+x))-(-3(x-1)-4+x)=0

We add all the numbers together, and all the variables

3(9-(x+1))-(-3(x-1)-4+x)+4=0



We calculate terms in parentheses: -(-3(x-1)-4+x), so:

-3(x-1)-4+x

determiningTheFunctionDomain
-3(x-1)+x-4

We add all the numbers together, and all the variables

x-3(x-1)-4

We multiply parentheses

x-3x+3-4

We add all the numbers together, and all the variables

-2x-1

Back to the equation:

-(-2x-1)



We get rid of parentheses

3(9-(x+1))+2x+1+4=0

We add all the numbers together, and all the variables

2x+3(9-(x+1))+5=0

We move all terms containing x to the left, all other terms to the right

2x+3(9-(x+1))=-5

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