4+3(n-5)=19

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Solution for 4+3(n-5)=19 equation:



4+3(n-5)=19
We move all terms to the left:
4+3(n-5)-(19)=0
We add all the numbers together, and all the variables
3(n-5)-15=0
We multiply parentheses
3n-15-15=0
We add all the numbers together, and all the variables
3n-30=0
We move all terms containing n to the left, all other terms to the right
3n=30
n=30/3
n=10

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