4+3(r-5)=-7(r+11)+6

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Solution for 4+3(r-5)=-7(r+11)+6 equation: 



4+3(r-5)=-7(r+11)+6

We move all terms to the left:

4+3(r-5)-(-7(r+11)+6)=0

We multiply parentheses

3r-(-7(r+11)+6)-15+4=0



We calculate terms in parentheses: -(-7(r+11)+6), so:

-7(r+11)+6

We multiply parentheses

-7r-77+6

We add all the numbers together, and all the variables

-7r-71

Back to the equation:

-(-7r-71)



We add all the numbers together, and all the variables

3r-(-7r-71)-11=0

We get rid of parentheses

3r+7r+71-11=0

We add all the numbers together, and all the variables

10r+60=0

We move all terms containing r to the left, all other terms to the right

10r=-60

r=-60/10

r=-6

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