4+3(t+5)=28-6t

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Solution for 4+3(t+5)=28-6t equation: 



4+3(t+5)=28-6t

We move all terms to the left:

4+3(t+5)-(28-6t)=0

We add all the numbers together, and all the variables

3(t+5)-(-6t+28)+4=0

We multiply parentheses

3t-(-6t+28)+15+4=0

We get rid of parentheses

3t+6t-28+15+4=0

We add all the numbers together, and all the variables

9t-9=0

We move all terms containing t to the left, all other terms to the right

9t=9

t=9/9

t=1

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