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4+3(x-4)=5(1+x)-1
We move all terms to the left:
4+3(x-4)-(5(1+x)-1)=0
We add all the numbers together, and all the variables
3(x-4)-(5(x+1)-1)+4=0
We multiply parentheses
3x-(5(x+1)-1)-12+4=0
We calculate terms in parentheses: -(5(x+1)-1), so:We add all the numbers together, and all the variables
5(x+1)-1
We multiply parentheses
5x+5-1
We add all the numbers together, and all the variables
5x+4
Back to the equation:
-(5x+4)
3x-(5x+4)-8=0
We get rid of parentheses
3x-5x-4-8=0
We add all the numbers together, and all the variables
-2x-12=0
We move all terms containing x to the left, all other terms to the right
-2x=12
x=12/-2
x=-6
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