4+3(x-5)=-7(x+11)+6

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Solution for 4+3(x-5)=-7(x+11)+6 equation: 



4+3(x-5)=-7(x+11)+6

We move all terms to the left:

4+3(x-5)-(-7(x+11)+6)=0

We multiply parentheses

3x-(-7(x+11)+6)-15+4=0



We calculate terms in parentheses: -(-7(x+11)+6), so:

-7(x+11)+6

We multiply parentheses

-7x-77+6

We add all the numbers together, and all the variables

-7x-71

Back to the equation:

-(-7x-71)



We add all the numbers together, and all the variables

3x-(-7x-71)-11=0

We get rid of parentheses

3x+7x+71-11=0

We add all the numbers together, and all the variables

10x+60=0

We move all terms containing x to the left, all other terms to the right

10x=-60

x=-60/10

x=-6

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