4+3/4(3n-20)=25

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Solution for 4+3/4(3n-20)=25 equation: 



4+3/4(3n-20)=25

We move all terms to the left:

4+3/4(3n-20)-(25)=0



Domain of the equation: 4(3n-20)!=0

n∈R



We add all the numbers together, and all the variables

3/4(3n-20)-21=0

We multiply all the terms by the denominator


-21*4(3n-20)+3=0

Wy multiply elements

-84n(3+3=0

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