4+3/4w=2+2/3ww=

Solution for 4+3/4w=2+2/3ww= equation:

4+3/4w=2+2/3ww=

We move all terms to the left:

4+3/4w-(2+2/3ww)=0


Domain of the equation: 4w!=0

w!=0/4

w!=0

w∈R



Domain of the equation: 3ww)!=0

w!=0/1

w!=0

w∈R


We add all the numbers together, and all the variables

3/4w-(2/3ww+2)+4=0

We get rid of parentheses

3/4w-2/3ww-2+4=0

We calculate fractions


9w/12w^2+(-8w)/12w^2-2+4=0

We add all the numbers together, and all the variables

9w/12w^2+(-8w)/12w^2+2=0

We multiply all the terms by the denominator


9w+(-8w)+2*12w^2=0

Wy multiply elements

24w^2+9w+(-8w)=0

We get rid of parentheses

24w^2+9w-8w=0

We add all the numbers together, and all the variables

24w^2+w=0

a = 24; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·24·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*24}=\frac{-2}{48}
=-1/24
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*24}=\frac{0}{48}
=0
$