4+3c(T+5)=48

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Solution for 4+3c(T+5)=48 equation:



4+3c(+5)=48
We move all terms to the left:
4+3c(+5)-(48)=0
We add all the numbers together, and all the variables
3c5+4-48=0
We add all the numbers together, and all the variables
3c^5-44=0
We do not support ecpression: c^5

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