4+3x=9-10(x-2)

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Solution for 4+3x=9-10(x-2) equation: 



4+3x=9-10(x-2)

We move all terms to the left:

4+3x-(9-10(x-2))=0



We calculate terms in parentheses: -(9-10(x-2)), so:

9-10(x-2)

determiningTheFunctionDomain
-10(x-2)+9

We multiply parentheses

-10x+20+9

We add all the numbers together, and all the variables

-10x+29

Back to the equation:

-(-10x+29)



We get rid of parentheses

3x+10x-29+4=0

We add all the numbers together, and all the variables

13x-25=0

We move all terms containing x to the left, all other terms to the right

13x=25

x=25/13

x=1+12/13

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