4+4(3w-3)=-2(2w-4)+6w

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Solution for 4+4(3w-3)=-2(2w-4)+6w equation: 



4+4(3w-3)=-2(2w-4)+6w

We move all terms to the left:

4+4(3w-3)-(-2(2w-4)+6w)=0

We multiply parentheses

12w-(-2(2w-4)+6w)-12+4=0



We calculate terms in parentheses: -(-2(2w-4)+6w), so:

-2(2w-4)+6w

We add all the numbers together, and all the variables

6w-2(2w-4)

We multiply parentheses

6w-4w+8

We add all the numbers together, and all the variables

2w+8

Back to the equation:

-(2w+8)



We add all the numbers together, and all the variables

12w-(2w+8)-8=0

We get rid of parentheses

12w-2w-8-8=0

We add all the numbers together, and all the variables

10w-16=0

We move all terms containing w to the left, all other terms to the right

10w=16

w=16/10

w=1+3/5

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