4+4(4u-1)=-2(2u-6)+6u

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Solution for 4+4(4u-1)=-2(2u-6)+6u equation:



4+4(4u-1)=-2(2u-6)+6u
We move all terms to the left:
4+4(4u-1)-(-2(2u-6)+6u)=0
We multiply parentheses
16u-(-2(2u-6)+6u)-4+4=0
We calculate terms in parentheses: -(-2(2u-6)+6u), so:
-2(2u-6)+6u
We add all the numbers together, and all the variables
6u-2(2u-6)
We multiply parentheses
6u-4u+12
We add all the numbers together, and all the variables
2u+12
Back to the equation:
-(2u+12)
We add all the numbers together, and all the variables
16u-(2u+12)=0
We get rid of parentheses
16u-2u-12=0
We add all the numbers together, and all the variables
14u-12=0
We move all terms containing u to the left, all other terms to the right
14u=12
u=12/14
u=6/7

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