4+4(5x-5)=8-4(2x+1)

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Solution for 4+4(5x-5)=8-4(2x+1) equation: 



4+4(5x-5)=8-4(2x+1)

We move all terms to the left:

4+4(5x-5)-(8-4(2x+1))=0

We multiply parentheses

20x-(8-4(2x+1))-20+4=0



We calculate terms in parentheses: -(8-4(2x+1)), so:

8-4(2x+1)

determiningTheFunctionDomain
-4(2x+1)+8

We multiply parentheses

-8x-4+8

We add all the numbers together, and all the variables

-8x+4

Back to the equation:

-(-8x+4)



We add all the numbers together, and all the variables

20x-(-8x+4)-16=0

We get rid of parentheses

20x+8x-4-16=0

We add all the numbers together, and all the variables

28x-20=0

We move all terms containing x to the left, all other terms to the right

28x=20

x=20/28

x=5/7

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