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4+4(x-2)=2(x+1)-x
We move all terms to the left:
4+4(x-2)-(2(x+1)-x)=0
We multiply parentheses
4x-(2(x+1)-x)-8+4=0
We calculate terms in parentheses: -(2(x+1)-x), so:We add all the numbers together, and all the variables
2(x+1)-x
We add all the numbers together, and all the variables
-1x+2(x+1)
We multiply parentheses
-1x+2x+2
We add all the numbers together, and all the variables
x+2
Back to the equation:
-(x+2)
4x-(x+2)-4=0
We get rid of parentheses
4x-x-2-4=0
We add all the numbers together, and all the variables
3x-6=0
We move all terms containing x to the left, all other terms to the right
3x=6
x=6/3
x=2
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