4+4x-5(3x-3)=4(3x-4)

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Solution for 4+4x-5(3x-3)=4(3x-4) equation: 



4+4x-5(3x-3)=4(3x-4)

We move all terms to the left:

4+4x-5(3x-3)-(4(3x-4))=0

We multiply parentheses

4x-15x-(4(3x-4))+15+4=0



We calculate terms in parentheses: -(4(3x-4)), so:

4(3x-4)

We multiply parentheses

12x-16

Back to the equation:

-(12x-16)



We add all the numbers together, and all the variables

-11x-(12x-16)+19=0

We get rid of parentheses

-11x-12x+16+19=0

We add all the numbers together, and all the variables

-23x+35=0

We move all terms containing x to the left, all other terms to the right

-23x=-35

x=-35/-23

x=1+12/23

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