4+5(4a+4)=58+3(5a+2)

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Solution for 4+5(4a+4)=58+3(5a+2) equation: 



4+5(4a+4)=58+3(5a+2)

We move all terms to the left:

4+5(4a+4)-(58+3(5a+2))=0

We multiply parentheses

20a-(58+3(5a+2))+20+4=0



We calculate terms in parentheses: -(58+3(5a+2)), so:

58+3(5a+2)

determiningTheFunctionDomain
3(5a+2)+58

We multiply parentheses

15a+6+58

We add all the numbers together, and all the variables

15a+64

Back to the equation:

-(15a+64)



We add all the numbers together, and all the variables

20a-(15a+64)+24=0

We get rid of parentheses

20a-15a-64+24=0

We add all the numbers together, and all the variables

5a-40=0

We move all terms containing a to the left, all other terms to the right

5a=40

a=40/5

a=8

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