4+5+(2x-3)=x-(3x+10)5+2(2x+3)=3(x+10)

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Solution for 4+5+(2x-3)=x-(3x+10)5+2(2x+3)=3(x+10) equation: 



4+5+(2x-3)=x-(3x+10)5+2(2x+3)=3(x+10)

We move all terms to the left:

4+5+(2x-3)-(x-(3x+10)5+2(2x+3))=0

We add all the numbers together, and all the variables

(2x-3)-(x-(3x+10)5+2(2x+3))+9=0

We get rid of parentheses

2x-(x-(3x+10)5+2(2x+3))-3+9=0



We calculate terms in parentheses: -(x-(3x+10)5+2(2x+3)), so:

x-(3x+10)5+2(2x+3)

We multiply parentheses

x-15x+4x-50+6

We add all the numbers together, and all the variables

-10x-44

Back to the equation:

-(-10x-44)



We add all the numbers together, and all the variables

2x-(-10x-44)+6=0

We get rid of parentheses

2x+10x+44+6=0

We add all the numbers together, and all the variables

12x+50=0

We move all terms containing x to the left, all other terms to the right

12x=-50

x=-50/12

x=-4+1/6

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