4+6(n-2)=3n-5(4n-3)

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Solution for 4+6(n-2)=3n-5(4n-3) equation:



4+6(n-2)=3n-5(4n-3)
We move all terms to the left:
4+6(n-2)-(3n-5(4n-3))=0
We multiply parentheses
6n-(3n-5(4n-3))-12+4=0
We calculate terms in parentheses: -(3n-5(4n-3)), so:
3n-5(4n-3)
We multiply parentheses
3n-20n+15
We add all the numbers together, and all the variables
-17n+15
Back to the equation:
-(-17n+15)
We add all the numbers together, and all the variables
6n-(-17n+15)-8=0
We get rid of parentheses
6n+17n-15-8=0
We add all the numbers together, and all the variables
23n-23=0
We move all terms containing n to the left, all other terms to the right
23n=23
n=23/23
n=1

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