4+6(n-2)=3n-5(4n-3)

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Solution for 4+6(n-2)=3n-5(4n-3) equation: 



4+6(n-2)=3n-5(4n-3)

We move all terms to the left:

4+6(n-2)-(3n-5(4n-3))=0

We multiply parentheses

6n-(3n-5(4n-3))-12+4=0



We calculate terms in parentheses: -(3n-5(4n-3)), so:

3n-5(4n-3)

We multiply parentheses

3n-20n+15

We add all the numbers together, and all the variables

-17n+15

Back to the equation:

-(-17n+15)



We add all the numbers together, and all the variables

6n-(-17n+15)-8=0

We get rid of parentheses

6n+17n-15-8=0

We add all the numbers together, and all the variables

23n-23=0

We move all terms containing n to the left, all other terms to the right

23n=23

n=23/23

n=1

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