4+a=6a-5(a+3)

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Solution for 4+a=6a-5(a+3) equation: 



4+a=6a-5(a+3)

We move all terms to the left:

4+a-(6a-5(a+3))=0



We calculate terms in parentheses: -(6a-5(a+3)), so:

6a-5(a+3)

We multiply parentheses

6a-5a-15

We add all the numbers together, and all the variables

a-15

Back to the equation:

-(a-15)



We get rid of parentheses

a-a+15+4=0

We add all the numbers together, and all the variables

19!=0

There is no solution for this equation

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