4+a=6a-5(a+3)

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Solution for 4+a=6a-5(a+3) equation:



4+a=6a-5(a+3)
We move all terms to the left:
4+a-(6a-5(a+3))=0
We calculate terms in parentheses: -(6a-5(a+3)), so:
6a-5(a+3)
We multiply parentheses
6a-5a-15
We add all the numbers together, and all the variables
a-15
Back to the equation:
-(a-15)
We get rid of parentheses
a-a+15+4=0
We add all the numbers together, and all the variables
19!=0
There is no solution for this equation

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